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Linear Algebra
Step 5 of 22

Independence

Understand first: span and basis

You have seen redundancy twice now: (2,4)(2,4) added nothing to (1,2)(1,2). Time to make that precise, because "points in a different direction" is not yet a test you can apply.

The definition, built from the failure

Vectors are linearly dependent when one of them can be written as a linear combination of the others. It sits inside the span of the rest, so it extends nothing.

(1,2)(1,2) and (2,4)(2,4): dependent, since (2,4)=2(1,2)(2,4) = 2(1,2).

(1,2)(1,2) and (0,1)(0,1): independent. No scalar multiple of (1,2)(1,2) produces (0,1)(0,1), because that would require the first coordinate 1c=01 \cdot c = 0, forcing c=0c = 0, which gives (0,0)(0,0) instead.

Rotate the second vector in the visual. Almost always the pair spans the plane; at the exact instant it aligns with the first, the span snaps down to a line.

Three vectors in a plane

Take (1,0)(1,0), (0,1)(0,1), and (3,5)(3,5). The first two already reach everywhere, so the third is reachable too: (3,5)=3(1,0)+5(0,1)(3,5) = 3(1,0) + 5(0,1). Dependent.

This is forced, not bad luck. In a plane, any three vectors are dependent. Two independent directions already exhaust the plane, so a third has nowhere new to point. In 3D space, any four vectors are dependent, for the same reason.

Why this is the pivot of Act I

Independence is what makes a basis a basis: a basis is exactly a set that is independent and spans.

It also decides the size of things. A plane needs 2 independent vectors, no more and no fewer. That count is forced by the space itself, not by your choice of basis — and a forced number is worth naming.

Next: naming it, and finding the flat worlds hiding inside bigger spaces.